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Van Der Waals Attractions: Summary Questions
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<font face="Verdana, Arial, Helvetica, sans-serif" size="5" color="#FFFFFF"><strong>Van Der Waals Attractions:</strong> Summary Questions</font>
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<td><font face="Verdana, Arial, Helvetica, sans-serif" size="4">You have explored the different types of van der Waals attractions, what factors affect the strength of these attractions, and how the strength of attractions affects the properties of a substance. Please answer the questions below to summarize what you have learned.</font></td>
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<font size="4" face="Arial, Helvetica, sans-serif"><strong>1) Which of the
following is NOT an attractive force between molecules:</strong></font>
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London dispersion
dipoloe-diople
covalent bond
hydrogen bond
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<font size="4" face="Arial, Helvetica, sans-serif"><strong>2) Which
factors affect the strength of the van der Waals attractions? (check all
that apply)</strong></font>
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the color of the molecules
the polarity of the molecules
the shape of the molecules
the size of the molecules
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<font size="4" face="Arial, Helvetica, sans-serif"><strong>3) You have two
substances: A and B. Both have molecules of similar size and shape.
Substance A has molecules that attract with London dispersion attraction,
and substance B has molecules that attract with dipole-dipole attraction.
Which one will have the higher boiling point?</strong></font>
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Substance A
Substance B
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<font size="4" face="Arial, Helvetica, sans-serif"><strong>4) Explain why
you chose Substance A or B.</strong></font>
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<font size="4" face="Arial, Helvetica, sans-serif"><strong>5) You have two
substances, both of which have the same boiling point (or attraction
between their molecules). The first substance is made from molecules that
are small (just a few atoms bonded together), and the second substance is
made from molecules that are larger (many atoms bonded together). How can
it be possible for two such different molecules to yield substances with
the same boiling point? Describe the kinds of van der Waals attractions
that must be involved and any other properties of the molecules that could
cause this result.</strong></font>
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