UTF-8Transfer of Kinetic Energy between hot and cold particles of same mass Name: La'Teese Hall
What happens when "Heat" flows from hot molecules to cold molecules?
The molecules in this simulation are colored according to how much kinetic energy they have. Molecules
with a lot of kinetic energy ones are red -- we call them hot. Cold ones are white.
Between the hot and cold molecules is a rigid barrier made of heavy atoms that bond tightly to
each other. Can Heat "flow" from the hot to the cold molecules? How does this happen?
Run the simulation to see. Watch the graph which shows the average Kinetic Energy/particle for the
gas molecules on the right, the gas molecules on the left, and the atoms in the barrier.
Does the average KE of the molecules on the right and left change? (Yes it does for both) What eventually happens to the KEs? (They come to an equilibrium)
What do we mean when we say the molecules on the right and left eventually reach "Thermal equilibrium"?
When all the Kinetic energys are at the same level.
Would you expect this process to reverse itself and for "heat to flow" from the left BACK to the right side?
No the process would not reverse itself.
I attempted to reduce the amount of KE transfer between both sides and the barrier by putting two barriers of particles on each side of the main barrier (window) and adding 1000 Resistance and 100 Damping force on them. Also, the interaction of both of the particles that would interact with each other were changed so that they would not have much interaction. Before coming up with this simulation I tried using just 500 Restraint which produced a lot of heat in the individual barriers that eventually ended up transfering the kinetic energy. After that I increased it but still realized that there was still heat being transfered so I added the damping force which slows down the particles. In the end, it starts off decent on the left side...but onthe right side I need to destroy and build another wall because this one tends to allow at least one particle to enter causing an interaction with the barrier and this in turn brings down the KE of the right side to be equal to the barrier.
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